Complete Array-2

[satish-paraddi]

No description provided.

[super30admin]

Find All Numbers Disappeared in an Array (Problem_1.py)

Excellent work! Your solution demonstrates a strong understanding of the problem and implements an optimal algorithm. Here are some specific points:

Strengths:

• You correctly identified and implemented the in-place negation technique, which is the standard optimal solution
• Your time complexity of O(n) is optimal and meets the follow-up requirement
• Your space complexity of O(1) is optimal
• The code is clean, readable, and well-commented
• Good use of abs() to handle previously negated values

Suggestions for further improvement:

• Consider adding inline comments to explain the algorithm's logic (e.g., why we use abs(nums[i]) - 1 and why we check nums[j] > 0)
• You could add a brief docstring explaining the approach for future reference
• Consider edge cases in your testing: empty array, array with all unique numbers, array with all duplicates

Comparison with reference: Your solution is significantly better than the reference solution in terms of time complexity (O(n) vs O(n²)) while maintaining the same space complexity. The reference solution would actually receive a Time Limit Exceeded on LeetCode for large inputs.

VERDICT: PASS

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max and min (Problem_2.py)

It appears you have submitted a solution for the "Game of Life" problem instead of the "max and min" problem. These are completely different problems:

• Game of Life: Simulates cellular automaton rules on a 2D board
• Max and Min: Find the minimum and maximum values in an array using fewer than 2*(N-2) comparisons

To solve the actual problem, you need to:

1. Take an array of numbers as input
2. Find both the minimum and maximum values
3. Use fewer than 2*(N-2) comparisons (the optimal approach uses about 1.5*(N-2) comparisons by processing elements in pairs)

A correct approach would be:

• Compare pairs of elements first (1 comparison per pair)
• Then compare the smaller with current min and larger with current max (2 more comparisons per pair)
• This gives 3 comparisons per 2 elements = 1.5*(N-2) comparisons total

Please resubmit with the correct solution for the max and min problem.

VERDICT: NEEDS_IMPROVEMENT

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Game of Life

Excellent work! Your solution for the Game of Life problem is correct, efficient, and well-implemented. Here are some specific points:

Strengths:

• Your solution correctly implements the in-place encoding technique using values 2 and 3 as intermediate states
• The two-pass approach correctly handles the simultaneous update requirement
• The code is clean, readable, and follows Python conventions
• Time and space complexity match the optimal solution

Minor suggestions for improvement:

• Consider adding a brief comment explaining what values 2 and 3 represent (e.g., # 2: live->dead, 3: dead->live) to improve code documentation
• The getCount function could be slightly optimized by inlining the direction checks, but this is a minor stylistic choice
• Consider adding edge case handling documentation in comments

Overall: Your solution demonstrates a strong understanding of the problem and the optimal in-place approach. The implementation is essentially identical to the reference solution in terms of algorithm and efficiency.

VERDICT: PASS