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Challenge 9: threads are not executed in parallel but one by one #2

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@deimi

In your implementation the list of threads will only contain one thread at a time, which gets immediately started and joined. So in the end nothing will run in parallel

The actual solution should look like this

threads = []
for scribe in self.scribes:
    if len(scribe.moves) > i:
        args = scribe.moves[i][1]+[self]
        threads.append(Thread(target=scribe.moves[i][0], args=args))
[thread.start() for thread in threads]
[thread.join() for thread in threads]
self.print()

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